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A light bulb is rated 100W for 220 V AC supply of 50 Hz. Calculate (a) resistance of the bulb. (b) the rms current through the bulb.

by Manoj Jaiswar ( PMJ Sir ) November 03, 2023

the given can be listed as

Power P = 100W

$V_{rms}=220 V$

To Find , Resistance R = ?

$I_{rms}=?$

Solution -

$R=\frac{V_{rms}^{2}}{P}=\frac{220\mathrm{x}220}{100}=484\Omega$

$I_{rms}=\frac{P}{V_{rms}}=\frac{100}{220}=\frac{1}{2.2}=0.45A$

AC Circuit Class 12 Maharashtra State Board

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Posted by Manoj Jaiswar ( PMJ Sir )

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